1/7x^2-5x=0

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Solution for 1/7x^2-5x=0 equation: 


x in (-oo:+oo)

(1/7)*x^2-(5*x) = 0

(1/7)*x^2-5*x = 0

1/7*x^2-5*x = 0

DELTA = (-5)^2-(0*1/7*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+5)/(1/7*2) or x = (5-25^(1/2))/(1/7*2)

x = 35 or x = 0

x in { 0, 35 }

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